Our Ib Math tutors understand that calculus is one of the most important topics. 40 teaching hours are given for Sl calculus(27% of total time) and 48 hours are given for HL calculus(20% of total time) and that is maximum in IB math. After understanding the importance of calculus we have written many posts on this topic. A few of them are:
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The formula by which any positive integral power of a binomial expression can be expanded in the form of a series is known as Binomial Theorem. If x, y ∈ R and n∈N, then
(x + y)n = nC0 xn + nC1 xn-1 y + nC2 xn-2y2 + ….. + nCrxn-r yr + ….. + nCnyn =nCr xn – r yr
This theorem can be proved by Induction method.
(i) The number of terms in the expansion is (n + 1) i.e. one or more than the index.
(ii) The sum of the indices of x & y in each term is n.
(iii) The binomial coefficients of the terms nC0, nC1…….. equidistant from the beginning and the end are equal. Read more
geometric explanation of diﬀerentiation
Geometric explanation of diﬀerentiation- If we find the derivative of function f(x) at x = x0 then it is equal to the slope of the tangent to the graph of given function f(x) at the given point [(x0, f(x0))].
But what is a tangent line?
►It is not merely a simple line that joins the graph of given function at one point.
►It is actually the limit of the secant lines joining points P = [(x0, f(x0)] and Q on the graph of f(x) as Q moves very much close to P.
The tangent line contacts the graph of given function at the given point [(x0, f(x0)] the slope of the tangent line matches the direction of the graph at that point. The tangent line is the straight line that best approximates the graph at that point.
As we are given the graph of given function, we can draw the tangent to this graph easily. Still, we’ll like to make calculations involving the tangent line and so will require a calculative method to explore the tangent line.
We can easily calculate the equation of the tangent line by using the slope-point form of the line. We slope of a line is m and its passing through a point (x0,y0) then its equation will be
y − y0 = m(x − x0)
So now we have the formula for the equation of the tangent line. It’s clear that to get an actual equation for the tangent line, we should know the exact coordinates of point P. If we have the value of x0 with us we calculate y0 as
y = f(x0)
The second thing we must know is the slope of line
m = f’(x0)
Which we call the derivative of given function f(x).
The derivative f’(x0) of given function f at x0 is equal to the slope of the tangent line to
y = f(x) at the point P = (x0, f(x0).
Differentiation Using Formulas- We can use derivatives of different types of functions to solve our problems :
(ix) D (secx) = secx . tanx (x) D (cosecx) = – cosecx . cotx
(xii) D (constant) = 0 where D =
These formulas are result of differetiation by first principle
Inverse Functions And Their Derivatives :
Theorems On Derivatives: If u and v are derivable function of x, then,
(i) (ii) where K is any constant
(iii) known as “ Product Rule ” (iv)
known as “Quotient Rule ”
(v) If y = f(u) & u = g(x) then “Chain Rule ”
Logarithmic Differentiation: To find the derivative of : (i) a function which is the product or quotient of a number of functions OR
(ii) a function of the form where f & g are both differentiable, it will be found convenient to take the logarithm of the function first & then differentiate. This is called Logarithmic Differentiation.
Implicit Differentiation: (i) In order to find dy/dx, in the case of implicit functions, we differentiate each term w.r.t. x regarding y as a function of x & then collect terms in dy/dx together on one side to finally find dy/dx.
(ii) In answers of dy/dx in the case of implicit functions, both x & y are present.
Parametric Differentiation: If y = f(q) & x = g(q) where q is a parameter, then
Derivative Of A Function w.r.t. Another Function-: Let y = f(x) & z = g(x)
Derivatives Of Order Two & Three: Let a function y = f(x) be defined on an open interval (a, b). It’s derivative, if it exists on(a, b) is a certain function f'(x) [or (dy/dx) or y’ ] & is called the first derivative of y w.r.t. x. If it happens that the first derivative has a derivative on (a, b) then this derivative is called the second derivative of y w. r. t. x & is denoted by f”(x) or (d2y/dx2) or y”. Similarly, the 3rd order derivative of y w. r. t. X, if it exists, is defined by It is also denoted by f”'(x) or y”’.
All maths tutors suggest solving a fair amount of questions based on the geometric explanation of diﬀerentiation
Example-Find the tangent line to the following function at z=3 for the given function
We can find the derivative of the given function using basic differentiation as discussed in the previous post
We are already given that z=3 so
Equation of tangent line is
y − y0 = m(x − x0) here y0=R(3)=√7
Putting these values we get equation of tangent line
So that’s all for the geometric explanation of diﬀerentiation, I will discuss Application of Derivatives in my next post
Example- Differentiate the following function
Ans: We can apply quotient rule in this questions
You can try these questions in the meantime
In my IB Mathematics Tutors series, I will explain different topics taught at HL and SL levels of IB Mathematics. Calculus is the first one.
If we want to understand the importance of Calculus in IB Diploma Programme, We should have a look at the number of teaching hours recommended for it. It’s 40 hours in SL(out of 150 total hours) and 48 (out of 240 total hours) hours in HL. This makes calculus the most important topic for IB Mathematics Tutors as well as for IB students.
What is Calculus- Calculus is an ancient Latin word. It means ‘small stones’ used for counting. In every branch of Mathematics, we study of something specific, like in Geometry, we study about shapes, in Algebra, we study about arithmetic operations, in coordinate, we study about locating a point. In calculus, we do the mathematical study of continuous change. It mainly has two branches- Read more
In my previous post on IB Mathematics, I have discussed how to solve a quadratic polynomial using Quadratic formula. Here I will tell you about different relationships based on sum and product of quadratic polynomial, cubic polynomial and bi-quadratic polynomials.
ax2 + bx + c = 0
Sum of the roots = −b/a
Product of the roots = c/a
If we know the sum and product of the roots/zeros of a quadratic polynomial, then we can find that polynomial using this formula
x2 − (sum of the roots)x + (product of the roots) = 0 Read more