# Calculus (Part-2)-geometric explanation of diﬀerentiation

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**Geometric explanation of diﬀerentiation- **If we find the derivative of function f(x) at x = x_{0 }then it is equal to the slope of the tangent to the graph of given function f(x) at the given point [(x_{0}, f(x_{0}))].

But what is a tangent line?

**►**It is not merely a simple line that joins the graph of given function at one point.

**►**It is actually the limit of the secant lines joining points P = [(x_{0}, f(x_{0})] and Q on the graph of f(x) as Q moves very much close to P.

The tangent line contacts the graph of given function at given point [(x_{0}, f(x_{0})] the slope of the tangent line matches the direction of the graph at that point. The tangent line is the straight line that best approximates the graph at that point.

As we are given the graph of given function, we can draw the tangent to this graph easily. Still, we’ll like to make calculations involving the tangent line and so will require a calculative method to explore the tangent line.

We can easily calculate the equation of the tangent line by using the slope-point form of the line. We slope of a line is m and its passing through a point (x_{0},y_{0}) then its equation will be

** y − y _{0} = m(x − x_{0})**

So now we have the formula for the equation of the tangent line. It’s clear that to get an actual equation for the tangent line, we should know the exact coordinates of point P. If we have the value of x_{0 }with us we calculate y_{0 }as

** y = f(x _{0})**

The second thing we must know is the slope of line

** m = f’(x _{0})**

Which we call the derivative of given function f(x).

**Definition: **

The derivative f’(x_{0}) of given function f at x_{0} is equal to the slope of the tangent line to

y = f(x) at the point P = (x_{0}, f(x_{0}).

**Differentiation Using Formulas-** We can use derivatives of different types of functions to solve our problems :

(ix) D (secx) = secx . tanx (x) D (cosecx) = – cosecx . cotx

(xii) D (constant) = 0 where D =

These formulas are result of differetiation by first principle

**Inverse Functions And Their Derivatives :**

**Theorems On Derivatives: ** If u and v are derivable function of x, then,

(i) (ii) where K is any constant

(iii) known as “ Product Rule ” (iv)

known as “Quotient Rule ”

(v) If y = f(u) & u = g(x) then “Chain Rule ”

**Logarithmic Differentiation****:** To find the derivative of : (i) a function which is the product or quotient of a number of functions OR

(ii) a function of the form where f & g are both differentiable, it will be found convenient to take the logarithm of the function first & then differentiate. This is called *Logarithmic Differentiation .*

**Implicit Differentiation:** (i) In order to find dy/dx, in the case of implicit functions, we differentiate each term w.r.t. x regarding y as a function of x & then collect terms in dy/dx together on one side to finally find dy/dx.

(ii) In answers of dy/dx in the case of implicit functions, both x & y are present.

**Parametric Differentiation:** If y = f(q) & x = g(q) where q is a parameter, then

**Derivative Of A Function w.r.t. Another Function-**: Let y = f(x) & z = g(x)

**Derivatives Of Order Two & Three:** Let a function y = f(x) be defined on an open interval (a, b). It’s derivative, if it exists on(a, b) is a certain function f'(x) [or (dy/dx) or y’ ] & is called the first derivative of y w.r.t. x. If it happens that the first derivative has a derivative on (a, b) then this derivative is called the second derivative of y w. r. t. x & is denoted by f”(x) or (d^{2}y/dx^{2}) or y”. Similarly, the 3rd order derivative of y w. r. t. X, if it exists, is defined by It is also denoted by f”'(x) or y”’.

All online maths tutors suggest solving fair amount of questions based on these concepts

** Example-**Find the tangent line to the following function at z=3 for the given function

*Solution*

We can find the derivative of the given function using basic differentiation as discussed in the previous post

We are already given that z=3 so

Equation of tangent line is

** y − y _{0} = m(x − x_{0}) ** here y

_{0}=R(3)=√7

Putting these values we get equation of tangent line

In my online maths tutors series, I will discuss Application of Derivatives

** Example- ** Differentiate the following function

Ans: We can apply quotient rule in this questions

### You can try these questions in the meantime

### 28 – Differentiation (09-10-15) with answers.pdf

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### DifferentiationQuestionBankMathHl.pdf